Polynomial Function
A function of the form f(x) = a_n x^n + ... + a_1 x + a_0. The degree n determines end behavior and the maximum number of zeros.
Example: f(x) = 2x^3 - 5x^2 + 3x - 1 is degree 3 with at most 3 real zeros and 2 turning points.

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Session Length
~13 min
Adaptive Checks
12 questions
Transfer Probes
7
Polynomial and rational functions are central to AP Precalculus. Polynomials are built from powers of x; their degree determines end behavior and the maximum number of zeros and turning points.
Rational functions arise when one polynomial is divided by another, introducing vertical asymptotes, horizontal asymptotes, and holes. Mastering zeros, multiplicity, end behavior, asymptotic analysis, and polynomial division prepares students for calculus concepts like limits and continuity.
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A function of the form f(x) = a_n x^n + ... + a_1 x + a_0. The degree n determines end behavior and the maximum number of zeros.
Example: f(x) = 2x^3 - 5x^2 + 3x - 1 is degree 3 with at most 3 real zeros and 2 turning points.
If f(c)=0, then (x-c) is a factor. Zeros are where the graph crosses or touches the x-axis.
Example: f(x) = x^2 - 5x + 6 has zeros at x=2 and x=3 because f(x) = (x-2)(x-3).
How many times a factor (x-c) appears. Odd multiplicity: graph crosses the axis. Even multiplicity: graph bounces off.
Example: f(x) = (x-1)^2(x+2) has a double zero at x=1 (bounce) and a single zero at x=-2 (cross).
How f(x) behaves as x approaches positive or negative infinity. Determined by the leading term a_n x^n.
Example: For f(x) = -3x^4 + ..., both ends point down because degree is even and leading coefficient is negative.
A ratio of two polynomials: f(x) = p(x)/q(x). Domain excludes values where q(x) = 0.
Example: f(x) = (x+1)/(x^2-4) has domain all reals except x = 2 and x = -2.
A vertical line x = a where the function approaches infinity. Occurs where the denominator is zero but the numerator is not.
Example: f(x) = 1/(x-3) has a vertical asymptote at x = 3.
The value y = L that f(x) approaches as x goes to infinity. Determined by comparing degrees of numerator and denominator.
Example: f(x) = (2x+1)/(x-3) has HA y = 2 because degrees are equal and leading coefficients ratio is 2/1.
Points where both numerator and denominator are zero due to a common factor. The factor cancels but the point is undefined.
Example: f(x) = (x^2-1)/(x-1) = x+1 with a hole at x=1 (both top and bottom are zero there).
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Walk through a solved problem step-by-step. Try predicting each step before revealing it.
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